5m^2-25m+30=0

Solution for 5m^2-25m+30=0 equation:

5m^2-25m+30=0

a = 5; b = -25; c = +30;
Δ = b2-4ac
Δ = -252-4·5·30
Δ = 25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{25}=5$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-5}{2*5}=\frac{20}{10}
=2
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+5}{2*5}=\frac{30}{10}
=3
$